3x^2+33x-8.9=0

Solution for 3x^2+33x-8.9=0 equation:

3x^2+33x-8.9=0

a = 3; b = 33; c = -8.9;
Δ = b2-4ac
Δ = 332-4·3·(-8.9)
Δ = 1195.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-\sqrt{1195.8}}{2*3}=\frac{-33-\sqrt{1195.8}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+\sqrt{1195.8}}{2*3}=\frac{-33+\sqrt{1195.8}}{6}
$